Global Advances in Oncology: Regulation, Multimorbidity, Education, Diagnostics, Cardio-Oncology, and Equity

The Global Mosaic of Modern Oncology The Global Mosaic of Modern Oncology: How Breakthrough Care Meets Real-World Practice A radical transformation is taking place in cancer treatment. For decades the focus of oncology research was only biological; finding the cell mutations, finding drugs that target them and finding ways to make the tumour go away. Although molecular advancements keep changing the course of prognosis, there is a broader reality that has come to light. Nowadays, the fight against cancer doesn't focus solely on cure or control. Regulatory speed, comorbid health conditions, stress from the diagnostic process, cardiovascular side effects, doctor and nurse education, and social determinants of health (SDOH) all influence a patient's journey. Global efforts from expedient drug approval in the Middle East to overhauling cancer training in Europe are changing the face of cancer care into a more unified, fair, and patient...

Real Analysis & Calculus Revision Guide

Real Analysis

Complete Real Analysis & Calculus Revision Guide

Continuity • Uniform Continuity • Differentiability • Monotone Functions • Sequences • Limit Points • Topology & Theorems

1. Boundedness Theorem

If a function f is continuous on a closed interval [a,b], then it is bounded.

There exist real numbers M and m such that:

m ≤ f(x) ≤ M for all x ∈ [a,b]

Example

f(x)=x² on [-2,2]

Minimum value = 0

Maximum value = 4

Hence f(x) is bounded.

Continuous functions on closed intervals never "blow up" to infinity.

2. Extreme Value Theorem

If f is continuous on [a,b], then f attains both:

  • Absolute Maximum
  • Absolute Minimum

Example

f(x)=x² on [-1,2]

  • Minimum = 0 at x=0
  • Maximum = 4 at x=2

3. Intermediate Value Theorem (IVT)

If f is continuous on [a,b] and k lies between f(a) and f(b), then there exists c∈(a,b) such that:

f(c)=k

Example

f(x)=x³

f(1)=1 and f(2)=8

Since 5 lies between 1 and 8, there exists c∈(1,2) such that:

f(c)=5

4. Zero Existence Theorem

If:

f(a)·f(b) < 0

then there exists c∈(a,b) such that:

f(c)=0

Example

f(x)=x²−2

f(1)=-1

f(2)=2

Sign changes occur, therefore root exists between 1 and 2.

5. Continuity

A function is continuous at x=c if:

lim(x→c) f(x) = f(c)

Examples

Function Continuity
Continuous everywhere
|x| Continuous everywhere
1/x Discontinuous at x=0

6. Piecewise Continuity Example

Function (a)

f(x)=x for x<0
f(0)=0
f(x)=x² for x>0

Left-hand limit = 0

Right-hand limit = 0

Function is continuous everywhere.

Function (b)

f(x)=cos(x) for x<0
f(0)=1/2
f(x)=x² for x>0

LHL = 1

RHL = 0

LHL ≠ RHL, therefore discontinuous at x=0.

7. Uniform Continuity

Uniform continuity means the same δ works everywhere in the domain.

Important Results

Condition Result
Continuous on [a,b] Uniformly Continuous
Bounded Derivative Uniformly Continuous
Continuous Periodic Function Uniformly Continuous

Examples

Function Uniformly Continuous?
xsin(1/x) Yes
sin(1/x) No
1/x No
sin(x) Yes
|x| Yes
e^(-x²) Yes

8. Differentiability

f is differentiable at c if:

f'(c)=lim (f(x)-f(c))/(x-c)

Example

f(x)=x²

f'(x)=2x

Differentiable everywhere.

Continuity does not imply differentiability.

f(x)=|x|

Continuous at x=0 but not differentiable at x=0.

9. Left and Right Derivatives

Left Derivative:

Lf'(c)=lim x→c⁻ (f(x)-f(c))/(x-c)

Right Derivative:

Rf'(c)=lim x→c⁺ (f(x)-f(c))/(x-c)

Function is differentiable iff:

Lf'(c)=Rf'(c)

f(x)=|x|

Left derivative = -1

Right derivative = +1

Not differentiable at x=0.

10. Extreme Points

If f has a local maximum or minimum at interior point c and derivative exists, then:

f'(c)=0

Examples

Function Extremum
Minimum at x=0
-x² Maximum at x=0
f'(0)=0 but no extremum

11. Monotone Functions

A monotone function can only have jump discontinuities.

  • One-sided limits always exist.
  • Discontinuities are at most countable.
  • No oscillatory discontinuities.

12. Zeros of Continuous Functions

Let:

Z(f)={x : f(x)=0}

For continuous functions, Z(f) is always closed.

f(x)=sin(x)

Z(f)={nπ : n∈ℤ}

13. Dirichlet Function

f(x)=0 if x is rational
f(x)=1 if x is irrational

Discontinuous everywhere.

14. Modified Dirichlet Function

f(x)=0 if x is rational
f(x)=x²−1 if x is irrational

Continuous only at:

x=−1 and x=1

15. Sequences and Limit Points

Exactly k Limit Points

Create k subsequences converging to k different values.

Limit points {0,1,2}

xₙ= 0+1/n, n≡0(mod3)
1+1/n, n≡1(mod3)
2+1/n, n≡2(mod3)

Uncountably Many Limit Points

Possible.

Example: Enumeration of rationals in [0,1].

Limit point set = [0,1]

16. Sequence Whose Limit Point Set Is Entire ℝ

Enumerate all rational numbers in ℝ.

Since ℚ is dense in ℝ, every real number becomes a subsequential limit.

Limit point set = ℝ.

17. Characteristic Function

χE(x)=1 if x∈E
χE(x)=0 if x∉E

χE is continuous iff E is both open and closed (clopen).

18. Distance Function Example

φ(x)=min(|x−1|,|x−2|)

Continuous everywhere.

Not differentiable at:

  • x=1
  • x=3/2
  • x=2

Final Exam Checklist

  • Continuous on closed interval ⇒ bounded + attains extrema.
  • IVT guarantees intermediate values.
  • Bounded derivative ⇒ Uniform continuity.
  • Differentiable ⇒ Continuous.
  • Continuous does NOT imply differentiable.
  • Monotone ⇒ at most countably many discontinuities.
  • Zero set of continuous function is closed.
  • Dense sequences can have uncountably many limit points.

Uniform Continuity: Important Examples & Counterexamples

Uniform continuity is one of the most important topics in Real Analysis. A function is uniformly continuous if the same δ works for the entire domain. The following examples are frequently asked in examinations and competitive tests.

✅ Uniformly Continuous Functions

Function Domain Why Uniformly Continuous?
e-x² Derivative is bounded.
e-x-x² Derivative remains bounded.
e-x²+x Derivative is bounded due to exponential decay.
sin(√x) [0, ∞) Continuous and satisfies a Hölder-type estimate.
|x| Lipschitz continuous.
sin(x) Derivative cos(x) is bounded.
x Lipschitz continuous with constant 1.
ex (-∞, 0) Derivative ex ≤ 1.
log(x) (1, ∞) Derivative 1/x ≤ 1.
x sin(1/x) (0,1) Extends continuously at x = 0.
Quick Rule: If a function has a bounded derivative on its domain, then it is uniformly continuous.

❌ Not Uniformly Continuous Functions

Function Domain Reason
ex Derivative grows without bound.
ex (0, ∞) Unbounded growth.
log(x) (0, ∞) Derivative blows up near 0.
log(x) (0,1) Derivative 1/x becomes unbounded near 0.
1/x (0,1) Becomes unbounded near 0.
sin(1/x) (0,1) Oscillates infinitely fast near 0.
tan(πx/2) (0,1) Blows up as x → 1.
Common Exam Trick: A function may be continuous everywhere on its domain but still fail to be uniformly continuous because of rapid oscillation (like sin(1/x)) or unbounded growth (like 1/x and ex).

Summary Table

Uniformly Continuous Not Uniformly Continuous
e-x² ex on ℝ
e-x-x² ex on (0,∞)
e-x²+x 1/x on (0,1)
sin(√x) sin(1/x) on (0,1)
|x| log(x) on (0,∞)
sin(x) log(x) on (0,1)
x tan(πx/2) on (0,1)
ex on (-∞,0) -
log(x) on (1,∞) -
x sin(1/x) -

Comments

Popular posts from this blog

Understanding the Laplacian of 1/r and the Dirac Delta Function Mathematical Foundations & SageMath Insights

Heuristic Computation and the Discovery of Mersenne Primes

Neural Network Generalization in the Over-Parameterization Regime: Mechanisms, Benefits, and Limitations